To get the appropriate flow and ensure you have a sufficient pump, you must determine the system’s operating pressure. A hydraulic pump’s job is to create enough force to push the operating pressure of a structure to transport the hydraulic fluid at the appropriate pump flow rate. So, let’s understand How Much Power Does a Hydraulic Pump Need.

How Much Power Does a Hydraulic Pump Need?

How Much Power Does a Hydraulic Pump Need

It creates sufficient power to counteract pressure at the pump outlet caused by the load. When a hydraulic pump is turned on, it generates a vacuum at the pump inlet, which pulls liquid from the storage into the pump’s intake line and mechanically transports this liquid to the pump output, forcing it into the hydraulic system.

Types of Pumps and Power Uses

  • A Rotary Vane Pump

A rotary vane 380v hydraulic power pack pump is a positive-displacement pump made out of vanes attached to a rotor that revolves inside a chamber. In certain circumstances, these vanes can be changeable in length and tensioned to keep in touch with the pump’s walls as it spins. How the vanes are forced into contact with the pump housing and how the vane tips are machined is a significant component in vane pump design.

  • Gear Pump 

Gear pumps (with external teeth) (fixed displacement) are straightforward and cost-effective. The swept volume or displacement of hydraulic gear pumps will range between 1 and 200 milliliters. They have the lowest volumetric efficiency of any three fundamental pump types (gear, vane, and piston pumps.

Pressure is generated by the meshing of the gear teeth, which drive fluid around the gears and pressurize the outlet. The major goal is to establish a tight seal between the inside of the housing and the vane while minimizing wear and metal-to-metal contact. Spring-loaded vanes force the vane out of the spinning center and towards the pump housing.

  • Screw Pumps 

Screw pumps (fixed displacement) are made up of two Archimedes’ screws that are intermingled and housed in the same chamber. These pumps are designed to handle strong flows at low pressure. They were employed on ships with a constant pressure hydraulic system that ran the ship’s length, particularly to regulate ball valves. The main issue with screw pumps is that the hydraulic response force is transmitted in an axially opposite direction to the flow direction.

A 3-phase, induction-type, Design B motor is the most often utilized motor to power a hydraulic pump. Most open frame sizes have a service factor of 0.15, which implies that the motor may be overloaded by around 15% of the current listed on its nameplate if used in a typical temperature condition. The service factor of TEFC and explosion-resistant motors is 1.0. An electric motor can be overloaded for brief periods during the cycle as long as the average horsepower is less than the nameplate rating + service factor when applicable. The degree of intermittent overloading is up to the user. However, we recommend that the overload be no more than 25% above its nameplate current rating and last no more than 10% of the time necessary for a complete cycle.

Variables Required for Calculating the Power 

  • Volumetric Effectiveness

This is calculated by dividing the theoretical flow by the actual flow supplied by the pump at a particular pressure. The theoretical flow is derived by multiplying the displacement per revolution of a hydraulic pump by its driving speed.

For instance, if a hydraulic pump has a displacement of 100cc/rev and is run at 1000 RPM, the potential flow is 100 liters/minute.

  • Efficiency in Mechanical/Hydraulic Systems

The mechanical/hydraulic efficiency is calculated by dividing the theoretical torque needed to drive it by the actual torque needed to drive it. If the pump supplied flow at zero pressure, no force or torque would be necessary to drive it. We intuitively know this is not possible due to mechanical and fluid friction.

A pump’s mechanical/hydraulic efficiency is determined by dividing the theoretical torque required to drive it by the actual torque required.

  • Pump Efficiency 

Overall efficiency is used to calculate the drive power at a given flow and pressure. This is used to determine the driving power required by a hydraulic pump at a particular pump flow and pressure. So, both the measurements must be taken first to provide the dealer’s result.  Ideally, the hydraulic power required to run a pump is determined by these factors: Overall efficiency is simply the product of volumetric and mechanical/hydraulic efficiency. The following has been given below –  

  • The rate of mass flow
  • Density of liquid
  • Height difference


The main factor that anybody operating a pump should look into is the type of pump. After that, accordingly, they can put variables in the formulas given below and calculate. The volume and mechanical effectiveness will need to be calculated to get the final power.

By Karan Bhardwaj

Karan Bhardwaj, Founder of Geeknism worked as a Digital Marketer since 2012 and has expertise in Tech Niche. You can follow him on Facebook and Twitter.